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		<title>Ahnboyoung: /* Quiz */</title>
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		<updated>2014-06-02T16:07:05Z</updated>

		<summary type="html">&lt;p&gt;&lt;span class=&quot;autocomment&quot;&gt;Quiz&lt;/span&gt;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;{{Cat|Normal Distribution| 04}}&lt;br /&gt;
Normal distributions do not necessarily have the same means and standard deviations.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
;Standard normal distribution&lt;br /&gt;
A normal distribution with a mean of 0 and a standard deviation of 1&lt;br /&gt;
&lt;br /&gt;
=Area below Z=&lt;br /&gt;
:[[File:ClipCapIt-140602-164653.PNG]]&lt;br /&gt;
&lt;br /&gt;
* The first column titled &amp;quot;Z&amp;quot; contains values of the standard normal distribution; the second column contains the area below Z. &lt;br /&gt;
* Since the distribution has a mean of 0 and a standard deviation of 1, the Z column is equal to the number of standard deviations below (or above) the mean. &lt;br /&gt;
&lt;br /&gt;
;Example&lt;br /&gt;
* a Z of -2.5 represents a value 2.5 standard deviations below the mean. &lt;br /&gt;
* The area below Z is 0.0062.&lt;br /&gt;
&lt;br /&gt;
=Formula=&lt;br /&gt;
A value from any normal distribution can be transformed into its corresponding value on a standard normal distribution using the following formula:&lt;br /&gt;
 Z = (X - μ)/σ&lt;br /&gt;
&lt;br /&gt;
 Where:&lt;br /&gt;
 Z is the value on the standard normal distribution,&lt;br /&gt;
 X is the value on the original distribution,&lt;br /&gt;
 μ is the mean of the original distribution and&lt;br /&gt;
 σ is the standard deviation of the original distribution.&lt;br /&gt;
&lt;br /&gt;
;Example&lt;br /&gt;
As a simple application, what portion of a normal distribution with a mean of 50 and a standard deviation of 10 is below 26? Applying the formula, we obtain&lt;br /&gt;
 Z = (26 - 50)/10 = -2.4&lt;br /&gt;
* From the table above, we can see that 0.0082 of the distribution is below -2.4. &lt;br /&gt;
* There is no need to transform to Z if you use the applet as shown below.&lt;br /&gt;
[[File:ClipCapIt-140602-165355.PNG]]&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
=Standardizing the Distribution=&lt;br /&gt;
If all the values in a distribution are transformed to Z scores, then the distribution will have a mean of 0 and a standard distribution. &lt;br /&gt;
This process of transforming a distribution to one with a mean of 0 and a standard deviation of 1 is called standardizing the distribution&lt;br /&gt;
&lt;br /&gt;
=Quiz=&lt;br /&gt;
&amp;lt;quiz display=simple&amp;gt;&lt;br /&gt;
&lt;br /&gt;
{ A standard normal distribution has: &lt;br /&gt;
&lt;br /&gt;
|type=&amp;quot;()&amp;quot;}&lt;br /&gt;
-a mean of 1 and a standard deviation of 1&lt;br /&gt;
+a mean of 0 and a standard deviation of 1&lt;br /&gt;
-a mean larger than its standard deviation&lt;br /&gt;
-all scores within one standard deviation of the mean&lt;br /&gt;
&lt;br /&gt;
{&lt;br /&gt;
{{Show Answer|&lt;br /&gt;
a mean of 0 and a standard deviation of 1&lt;br /&gt;
&lt;br /&gt;
The standard normal distribution is defined as a normal distribution with a mean of 0 and a standard deviation of 1. &lt;br /&gt;
}}&lt;br /&gt;
}&lt;br /&gt;
&lt;br /&gt;
{ A number 1.5 standard deviations below the mean has a z score of:&lt;br /&gt;
&lt;br /&gt;
|type=&amp;quot;()&amp;quot;}&lt;br /&gt;
-1.5&lt;br /&gt;
+-1.5&lt;br /&gt;
-3&lt;br /&gt;
-more information is needed&lt;br /&gt;
&lt;br /&gt;
{&lt;br /&gt;
{{Show Answer|&lt;br /&gt;
-1.5&lt;br /&gt;
&lt;br /&gt;
Z is equal to the number of standard deviations below or above the mean. Numbers below the mean have negative Z scores. &lt;br /&gt;
}}&lt;br /&gt;
}&lt;br /&gt;
&lt;br /&gt;
{  A distribution has a mean of 16 and a standard deviation of 6. What is the Z score that corresponds with 25? &lt;br /&gt;
&lt;br /&gt;
|type=&amp;quot;{}&amp;quot;}&lt;br /&gt;
{ 1.5 }&lt;br /&gt;
&lt;br /&gt;
{&lt;br /&gt;
{{Show Answer|&lt;br /&gt;
1.5&lt;br /&gt;
&lt;br /&gt;
25 is 1.5 SDs above the mean: Z is (X - M)/SD. (25 - 16)/6 is 1.5 &lt;br /&gt;
}}&lt;br /&gt;
}&lt;br /&gt;
&lt;br /&gt;
{ A distribution has a mean of 18 and a standard deviation of 5. Use the table presented in this section to determine the proportion of the scores (area) below 6.&lt;br /&gt;
&lt;br /&gt;
|type=&amp;quot;{}&amp;quot;}&lt;br /&gt;
{ 0.0082 }&lt;br /&gt;
&lt;br /&gt;
{&lt;br /&gt;
{{Show Answer|&lt;br /&gt;
0.0082&lt;br /&gt;
&lt;br /&gt;
Z is= (X - M)/SD. (6 - 18)/5 equals to -2.40, Look at the table to see that the area below -2.40 is .0082.&lt;br /&gt;
}}&lt;br /&gt;
&lt;br /&gt;
&amp;lt;/quiz&amp;gt;&lt;br /&gt;
}&lt;/div&gt;</summary>
		<author><name>Ahnboyoung</name></author>
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