Ahnboyoung: /* Example */

2014-05-26T17:42:55Z

Example

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{{Cat|Probability| 07}}

The hypergeometric distribution is used to calculate probabilities when sampling without replacement.
* The probability can be calculated using the following formula based on the hypergeometric distribution:

[[File:ClipCapIt-140526-183536.PNG]]

k is the number of "successes" in the population
x is the number of "successes" in the sample
N is the size of the population
n is the number sampled
p is the probability of obtaining exactly x successes
kCx is the number of combinations of k things taken x at a time

The mean and standard deviation of the hypergeometric distribution are:

[[File:ClipCapIt-140526-184121.PNG]]

[[File:ClipCapIt-140526-184131.PNG]]

=Example=
Suppose you first randomly sample one card from a deck of 52.
* Then, without putting the card back in the deck you sample a second and then (again without replacing cards) a third.
* Given this sampling procedure, what is the probability that exactly two of the sampled cards will be aces (4 of the 52 cards in the deck are aces).

In this example,
* k = 4 because there are four aces in the deck,
* x = 2 because the problem asks about the probability of getting two aces,
* N = 52 because there are 52 cards in a deck, and
* n = 3 because 3 cards were sampled.

Therefore,

[[File:ClipCapIt-140526-183951.PNG]] = [[File:ClipCapIt-140526-184004.PNG]]

=Quiz=

<quiz display=simple>

{A wallet contains 3 $100 bills and 5 $1 bills. You randomly choose 4 bills. What is the probability that you will choose exactly 2 $100 bills?

|type="{}"}
{ 0.42857 | .42857 }

{
{{Show Answer|
0.42857
}}
}

Hypergeometric Distribution - Revision history

Ahnboyoung: /* Example */