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		<title>Ahnboyoung: /* Quiz */</title>
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		<updated>2014-05-24T18:15:47Z</updated>

		<summary type="html">&lt;p&gt;&lt;span class=&quot;autocomment&quot;&gt;Quiz&lt;/span&gt;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;{{Cat|Summarizing Distributions| 05}}&lt;br /&gt;
&lt;br /&gt;
This section covers the effects of linear transformations on measures of central tendency and variability. &lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&amp;#039;&amp;#039;&amp;#039;Example&amp;#039;&amp;#039;&amp;#039;&lt;br /&gt;
&lt;br /&gt;
Table below shows the temperatures of 5 cities to see the Linear transformation: temperatures of cities. &lt;br /&gt;
&lt;br /&gt;
{| class=&amp;quot;wikitable&amp;quot; style=&amp;quot;text-align: right;&amp;quot;&lt;br /&gt;
|-&lt;br /&gt;
! City&lt;br /&gt;
! Degrees Fahrenheit&lt;br /&gt;
! Degrees Centigrade&lt;br /&gt;
|-&lt;br /&gt;
| Houston&lt;br /&gt;
| 54&lt;br /&gt;
| 12.22&lt;br /&gt;
|-&lt;br /&gt;
| Chicago&lt;br /&gt;
| 37&lt;br /&gt;
| 2.78&lt;br /&gt;
|-&lt;br /&gt;
| Minneapolis&lt;br /&gt;
| 31&lt;br /&gt;
| -0.56&lt;br /&gt;
|-&lt;br /&gt;
| Miami&lt;br /&gt;
| 78&lt;br /&gt;
| 25.56&lt;br /&gt;
|-&lt;br /&gt;
| Phoenix&lt;br /&gt;
| 70&lt;br /&gt;
| 21.11&lt;br /&gt;
|-&lt;br /&gt;
| style=&amp;quot;background: white&amp;quot; |Mean&lt;br /&gt;
| style=&amp;quot;background: white&amp;quot; |54.000&lt;br /&gt;
| style=&amp;quot;background: white&amp;quot; |12.220&lt;br /&gt;
|-&lt;br /&gt;
| style=&amp;quot;background: white&amp;quot; | Median&lt;br /&gt;
| style=&amp;quot;background: white&amp;quot; |54.000&lt;br /&gt;
| style=&amp;quot;background: white&amp;quot; |12.220&lt;br /&gt;
|-&lt;br /&gt;
| style=&amp;quot;background: white&amp;quot; |Variance&lt;br /&gt;
| style=&amp;quot;background: white&amp;quot; |330.00&lt;br /&gt;
| style=&amp;quot;background: white&amp;quot; |101.852&lt;br /&gt;
|-&lt;br /&gt;
| style=&amp;quot;background: white&amp;quot; |SD&lt;br /&gt;
| style=&amp;quot;background: white&amp;quot; |18.166&lt;br /&gt;
| style=&amp;quot;background: white&amp;quot; |10.092&lt;br /&gt;
|}&lt;br /&gt;
&lt;br /&gt;
To transform the degrees Fahrenheit to degrees Centigrade, we use the formula&lt;br /&gt;
 C = 0.556F - 17.778&lt;br /&gt;
&lt;br /&gt;
To get the mean in Centigrade, you multiply the mean temperature in Fahrenheit by 0.556 and then subtract 17.778 . &lt;br /&gt;
 (0.556)(54) - 17.778 = 12.22.&lt;br /&gt;
* The same is true for the median. &lt;br /&gt;
* This relationship holds even if the mean and median are not identical as they are in the table above.&lt;br /&gt;
&lt;br /&gt;
* The formula for the standard deviation is just as simple: the standard deviation in degrees Centigrade is equal to the standard deviation in degrees Fahrenheit times 0.556. &lt;br /&gt;
* Since the variance is the standard deviation squared, the variance in degrees Centigrade is equal to 0.5562 times the variance in degrees Fahrenheit.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
If a variable X has a mean of μ, a standard deviation of σ, and a variance of σ2, then a new variable Y created using the linear transformation&lt;br /&gt;
 Y = bX + A&lt;br /&gt;
 will have a mean of bμ+A, a standard deviation of bσ, and a variance of b2σ2.&lt;br /&gt;
&lt;br /&gt;
=Quiz=&lt;br /&gt;
&amp;lt;quiz display=simple &amp;gt;&lt;br /&gt;
&lt;br /&gt;
{ You have 10 numbers. The mean is 5. You multiply each number in the group by 3. What is the new mean?&lt;br /&gt;
&lt;br /&gt;
|type=&amp;quot;{}&amp;quot;}&lt;br /&gt;
{ 15 }&lt;br /&gt;
&lt;br /&gt;
{&lt;br /&gt;
{{Show Answer|&lt;br /&gt;
15&lt;br /&gt;
&lt;br /&gt;
5x3 is 15&lt;br /&gt;
}}&lt;br /&gt;
}&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
{You have 8 numbers. The mean is 6. You add 5 to each number in the group. What is the new mean?&lt;br /&gt;
&lt;br /&gt;
|type=&amp;quot;{}&amp;quot;}&lt;br /&gt;
{ 11 }&lt;br /&gt;
&lt;br /&gt;
{&lt;br /&gt;
{{Show Answer|&lt;br /&gt;
6+5 is 11&lt;br /&gt;
}}&lt;br /&gt;
}&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
{ You have 12 numbers. The mean is 3, and the variance is 1. You multiply each number by 4. What is the new variance?&lt;br /&gt;
&lt;br /&gt;
|type=&amp;quot;{}&amp;quot;}&lt;br /&gt;
{ 16 }&lt;br /&gt;
&lt;br /&gt;
{&lt;br /&gt;
{{Show Answer|&lt;br /&gt;
1*(4&amp;lt;sup&amp;gt;2&amp;lt;/sup&amp;gt;) is 16&lt;br /&gt;
}}&lt;br /&gt;
}&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
{ You have 15 numbers. The mean is 10, and the variance is 4. You multiply each number by 3. What is the new standard deviation?&lt;br /&gt;
&lt;br /&gt;
|type=&amp;quot;{}&amp;quot;}&lt;br /&gt;
{ 6 }&lt;br /&gt;
&lt;br /&gt;
{&lt;br /&gt;
{{Show Answer|&lt;br /&gt;
3 x sqrt(4) is 6&lt;br /&gt;
}}&lt;br /&gt;
}&lt;br /&gt;
&lt;br /&gt;
{Your teacher decides that he will add 10 points to all of your test grades. Which statistic is not changed by this decision?&lt;br /&gt;
&lt;br /&gt;
|type=&amp;quot;()&amp;quot;}&lt;br /&gt;
-mean&lt;br /&gt;
-median&lt;br /&gt;
-mode&lt;br /&gt;
+standard deviation&lt;br /&gt;
&lt;br /&gt;
{&lt;br /&gt;
{{Show Answer|&lt;br /&gt;
standard deviation&lt;br /&gt;
&lt;br /&gt;
The mean, median, and mode will all increase by 10, but the standard deviation remains unchanged. &lt;br /&gt;
}}&lt;br /&gt;
}&lt;br /&gt;
&lt;br /&gt;
&amp;lt;/quiz&amp;gt;&lt;/div&gt;</summary>
		<author><name>Ahnboyoung</name></author>
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